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Cambridge IGCSE 0478 · Topic 1 · 1.1a

Binary &
Denary

Base-2 · Base-10 · Conversion Methods · Place Values

CSZoneCambridge IGCSE Computer Science 0478
Binary Number System

Base-2: Only 0s and 1s

Computers use binary (base-2) because electronic circuits are either on (1) or off (0). Each digit is a bit. A group of 8 bits is a byte.
1286432168421
2⁷2⁶2⁵2⁴2⁰
Convert 10110101 to denary: 128+32+16+4+1 = 181
Denary to Binary Conversion

Repeated Division by 2

Convert 45 to binary:
45 ÷ 2 = 22 remainder 1
22 ÷ 2 = 11 remainder 0
11 ÷ 2 = 5 remainder 1
5 ÷ 2 = 2 remainder 1
2 ÷ 2 = 1 remainder 0
1 ÷ 2 = 0 remainder 1
Read remainders bottom to top: 101101
Check: 32+8+4+1 = 45 ✓
Alternative: subtract the largest power of 2 that fits, repeat for the remainder
Binary to Denary Conversion

Summing the Place Values

Write the binary number under the column headers (128,64,32,16,8,4,2,1). Add up all columns that have a 1.
11001010 = 128+64+0+0+8+0+2+0 = 202
00110111 = 0+0+32+16+0+4+2+1 = 55
Cambridge 0478: you must be able to convert between binary and denary for 8-bit numbers
Exam Practice

Have a go at this question

Cambridge IGCSE 0478 style
Convert the denary number 137 to binary. Show your working.
2 marks
128+8+1 = 137 [1]. Binary: 10001001 [1].
Key Takeaways

What to Remember

Binary (base-2) uses only 0 and 1; denary (base-10) uses 0–9
Place values for 8-bit binary: 128, 64, 32, 16, 8, 4, 2, 1
Binary → denary: sum the place values where bit = 1
Denary → binary: subtract largest fitting power of 2 repeatedly, or divide by 2